UEFA Nations event
Paide Linnameeskond meet FK Hegelmann Litauen in UEFA Conference League Qualification, kicking off on 16.07.2026 at 16:00 UTC. European competition takes both sides out of their domestic routine and against opponents from other leagues across the continent — typically a step up in level, and a different kind of test. The sections below cover the history between them, current form and the goal numbers behind the match.
Paide Linnameeskond vs FK Hegelmann Litauen head-to-head
European football tends to produce repeat meetings over the years, so there is often some shared history to draw on — though a qualifying draw can pair two sides for the first time. Any meetings on record are listed below; a blank table simply means none yet.
Date Event Score 16.07.2026 Paide Linnameeskond vs FK Hegelmann Litauen 3 - 0 09.07.2026 FK Hegelmann Litauen vs Paide Linnameeskond 1 - 1
Paide Linnameeskond and FK Hegelmann Litauen recent form
Form carries over from domestic play, which makes it a reliable guide here too. The latest results for each side appear below, newest first, and may span different competitions.
Paide Linnameeskond:
Date Event Score 07.11.2026 Paide Linnameeskond vs Flora Tallinn 2 - 2 04.11.2026 Harju JK Laagri vs Paide Linnameeskond 4 - 1 31.10.2026 Parnu JK Vaprus vs Paide Linnameeskond 0 - 1
FK Hegelmann Litauen:
Date Event Score 31.10.2026 FK Hegelmann Litauen vs FK Kauno Zalgiris 1 - 4 24.10.2026 Transinvest vs FK Hegelmann Litauen 2 - 0 18.10.2026 Zalgiris Vilnius vs FK Hegelmann Litauen 4 - 1
Paide Linnameeskond vs FK Hegelmann Litauen goals
Goals scored and conceded so far, across all competitions, as a rough measure of attacking and defensive output:
- Paide Linnameeskond — 20 scored, 21 conceded.
- FK Hegelmann Litauen — 14 scored, 33 conceded.
Paide Linnameeskond vs FK Hegelmann Litauen odds
Bookmakers price the same tie differently, and on European nights those differences can be sharp. Odds-Fan lines up the licensed bookmakers' prices for Paide Linnameeskond vs FK Hegelmann Litauen side by side, so the strongest number on each outcome is easy to find.
